php下将图片以二进制存入mysql数据库中并显示的实现代码

网络整理 - 08-26

  php把图片存入mysql教程数据库教程中并在网页上显示,一般情况下并不需要将突破保存到数据库中,不论是异地备份还是什么的,都很麻烦,特殊需要的除外

 


If($Picture != "none") {
$PSize = filesize($Picture);
$mysqlPicture = addslashes(fread(fopen($Picture, "r"), $PSize));
mysql_connect($host,$username,$password) or die("Unable to connect to SQL server");
@mysql_select_db($db) or die("Unable to select database");
mysql_query("INSERT INTO Images (Image) VALUES ($mysqlPicture)") or die("Cant Perform Query");
}else {
echo"You did not upload any picture";
}

  //以img标签读取数据库中的图片的代码


mysql_connect($host,$username,$password) or die("Unable to connect to SQL server");
@mysql_select_db($db) or die("Unable to select database");
$result=mysql_query("SELECT * FROM Images") or die("Cant Perform Query");
While($row=mysql_fetch_object($result)) {
echo "<IMG SRC="Second.php3? PicNum=$row->PicNum">";

//如secoed.php文件代码如下
$result=mysql_query("SELECT * FROM Images WHERE PicNum=$PicNum") or die("Cant perform Query");
$row=mysql_fetch_object($result);
Header( "Content-type: image/gif");
echo $row->Image;